์˜น์•Œ์ด(1)

์˜น์•Œ์ด(1)#

ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

๋จธ์“ฑ์ด๋Š” ํƒœ์–ด๋‚œ ์ง€ 6๊ฐœ์›” ๋œ ์กฐ์นด๋ฅผ ๋Œ๋ณด๊ณ  ์žˆ์Šต๋‹ˆ๋‹ค.
์กฐ์นด๋Š” ์•„์ง โ€œayaโ€, โ€œyeโ€, โ€œwooโ€, โ€œmaโ€ ๋„ค ๊ฐ€์ง€ ๋ฐœ์Œ์„
์ตœ๋Œ€ ํ•œ ๋ฒˆ์”ฉ ์‚ฌ์šฉํ•ด ์กฐํ•ฉํ•œ(์ด์–ด ๋ถ™์ธ) ๋ฐœ์Œ๋ฐ–์— ํ•˜์ง€ ๋ชปํ•ฉ๋‹ˆ๋‹ค.
๋ฌธ์ž์—ด ๋ฐฐ์—ด babbling์ด ๋งค๊ฐœ๋ณ€์ˆ˜๋กœ ์ฃผ์–ด์งˆ ๋•Œ,
๋จธ์“ฑ์ด์˜ ์กฐ์นด๊ฐ€ ๋ฐœ์Œํ•  ์ˆ˜ ์žˆ๋Š” ๋‹จ์–ด์˜ ๊ฐœ์ˆ˜๋ฅผ returnํ•˜๋„๋ก
solution ํ•จ์ˆ˜๋ฅผ ์™„์„ฑํ•ด์ฃผ์„ธ์š”.

# input setting
problem_num = '์˜น์•Œ์ด(1)'

import os, sys
path = os.getcwd() + f'\\txt\\{problem_num}'  + '.txt'
sys.stdin = open(path,'r')
babbling = sys.stdin.readline().strip().split(',')
def solution(babbling):
    from itertools import permutations as per
    answer = 0
    possibles = ["aya", "ye", "woo", "ma"]
    for i in range(2,5):
        possibles.extend(''.join(x).strip() for x in per(["aya", "ye", "woo", "ma"],i))
    for i in babbling:
        if i.strip() in possibles:
            answer += 1
    return answer

print(solution(babbling))
3
  • itertools.permutations

  • strip